TSTP Solution File: NUM663^1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM663^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n004.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:56:52 EDT 2023
% Result : Theorem 3.54s 3.76s
% Output : Proof 3.54s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : NUM663^1 : TPTP v8.1.2. Released v3.7.0.
% 0.13/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n004.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Fri Aug 25 09:28:23 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.54/3.76 SZS status Theorem for theBenchmark.p
% 3.54/3.76 SZS output start Proof for theBenchmark.p
% 3.54/3.76 Clause #0 (by assumption #[]): Eq (Not (less x y) → Eq x y) True
% 3.54/3.76 Clause #1 (by assumption #[]): Eq (less y z) True
% 3.54/3.76 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), less Xx Xy → less Xy Xz → less Xx Xz) True
% 3.54/3.76 Clause #4 (by assumption #[]): Eq (Not (less x z)) True
% 3.54/3.76 Clause #9 (by clausification #[4]): Eq (less x z) False
% 3.54/3.76 Clause #10 (by clausification #[0]): Or (Eq (Not (less x y)) False) (Eq (Eq x y) True)
% 3.54/3.76 Clause #11 (by clausification #[10]): Or (Eq (Eq x y) True) (Eq (less x y) True)
% 3.54/3.76 Clause #12 (by clausification #[11]): Or (Eq (less x y) True) (Eq x y)
% 3.54/3.76 Clause #13 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), less a Xy → less Xy Xz → less a Xz) True
% 3.54/3.76 Clause #14 (by clausification #[13]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), less a a_1 → less a_1 Xz → less a Xz) True
% 3.54/3.76 Clause #15 (by clausification #[14]): ∀ (a a_1 a_2 : nat), Eq (less a a_1 → less a_1 a_2 → less a a_2) True
% 3.54/3.76 Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 : nat), Or (Eq (less a a_1) False) (Eq (less a_1 a_2 → less a a_2) True)
% 3.54/3.76 Clause #17 (by clausification #[16]): ∀ (a a_1 a_2 : nat), Or (Eq (less a a_1) False) (Or (Eq (less a_1 a_2) False) (Eq (less a a_2) True))
% 3.54/3.76 Clause #19 (by superposition #[17, 12]): ∀ (a : nat), Or (Eq (less y a) False) (Or (Eq (less x a) True) (Or (Eq False True) (Eq x y)))
% 3.54/3.76 Clause #21 (by clausification #[19]): ∀ (a : nat), Or (Eq (less y a) False) (Or (Eq (less x a) True) (Eq x y))
% 3.54/3.76 Clause #22 (by superposition #[21, 1]): Or (Eq (less x z) True) (Or (Eq x y) (Eq False True))
% 3.54/3.76 Clause #23 (by clausification #[22]): Or (Eq (less x z) True) (Eq x y)
% 3.54/3.76 Clause #24 (by superposition #[23, 9]): Or (Eq x y) (Eq True False)
% 3.54/3.76 Clause #26 (by clausification #[24]): Eq x y
% 3.54/3.76 Clause #27 (by backward demodulation #[26, 9]): Eq (less y z) False
% 3.54/3.76 Clause #31 (by superposition #[27, 1]): Eq False True
% 3.54/3.76 Clause #32 (by clausification #[31]): False
% 3.54/3.76 SZS output end Proof for theBenchmark.p
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